(4m^2+2m+7)/(2m+1)

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Solution for (4m^2+2m+7)/(2m+1) equation: 


D( m )

2*m+1 = 0

2*m+1 = 0

2*m+1 = 0

2*m+1 = 0 // - 1

2*m = -1 // : 2

m = -1/2

m in (-oo:-1/2) U (-1/2:+oo)

(4*m^2+2*m+7)/(2*m+1) = 0

4*m^2+2*m+7 = 0

4*m^2+2*m+7 = 0

DELTA = 2^2-(4*4*7)

DELTA = -108

DELTA < 0

1 = 0

1/(2*m+1) = 0

m belongs to the empty set

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